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11-4x^2=-85
We move all terms to the left:
11-4x^2-(-85)=0
We add all the numbers together, and all the variables
-4x^2+96=0
a = -4; b = 0; c = +96;
Δ = b2-4ac
Δ = 02-4·(-4)·96
Δ = 1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1536}=\sqrt{256*6}=\sqrt{256}*\sqrt{6}=16\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{6}}{2*-4}=\frac{0-16\sqrt{6}}{-8} =-\frac{16\sqrt{6}}{-8} =-\frac{2\sqrt{6}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{6}}{2*-4}=\frac{0+16\sqrt{6}}{-8} =\frac{16\sqrt{6}}{-8} =\frac{2\sqrt{6}}{-1} $
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